That inertia calc is for I beams. For a square hollow section, you basically calculate the inertia of the outer square and subtract the inertia of the inner square.
So outside is 5x5 = 5*5^3/12 = 52.08in^4
Inside = 5 - 2(3/8) square = (4.25)(4.25)^3/12 = 27.19in^4
Ixx = 52.08 - 27.19 = 24.89in^4
Since you have 3 beams above and below, triple that so Ixx = 24.89*3 =74.67in^4
At 50PSI you have 50 x 15" = 750lb/in
E = 29000000 PSI
L = 96"
y = 0.5h = 2.5"
Copied straight from
http://www.engineeringtoolbox.com/beam- ... _1312.html
---------------------------------------------------------------------------
Unit Load - q : 750 (lb/in)
Total Load : 72000 (lb)
Length of Beam - L : 96 (in)
Moment of Inertia - I : 74.7 (in4)
Modulus of Elasticity - E : 29000000 (psi)
Perp. distance from neutral axis - y : 2.5 (in)
Support Force - R1 : 36000 (lb)
Support Force - R2 : 36000 (lb)
Maximum Stress - ? :
28927 (psi)
Maximum Deflection - ? :
0.38 (in)
--------------------------------------------------------------------------
Alternatively, you can find an inertia table here
http://sketchup.engineeringtoolbox.com/ ... -c_79.html
They take 0.35" as the thickness, where I took 3/8" = 0.375"
Again, these are an estimated calc and likely to be high, as the pressure isn't fully distributed along the beams, only where the hoses press.